a) Candidate key = {ABE}
R(ABCDE) can be decomposed to R1(ABC), R2(BD) and R3(BE). this relation is in 2nf, 3nf and bcnf
b) Candidate key = {AB, BC, BD}
Decomposition into R1(ABC) & R2(ACD) gives a relation in 2NF as candidate key for R1 is {AB} and R2 is {C}.
Now, further decomposition of the relation R1 into R3(CD) and R4(AD) gives decomposition into 3NF. Thus, relations in 3NF will be R3, R4 and R1. This relation is in BCNF too.