Assuming $i=\sqrt{-1}$ and t is real number , $\int_{0}^{\Pi /3} e^{it}dt$
given ans is $\sqrt{3}/2 + i/2 , and i am getting \sqrt{3}/2-i/2$
i solved first put $e^{it}= cost +isint$ then and integrate , but in solution they first integrate $e^{it}$ then put the value of it ... but ans different ... why is this happening .. am i missing something ??