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Prime implicants
Ashwani Kumar 2
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Digital Logic
Sep 22, 2017
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Given Boolean expression
F(A,B,C,D) = $\sum m(0,1,2,5,7,8,10,12,14,15)$
The possible number of essential prime implicants are_______
Ashwani Kumar 2
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Digital Logic
Sep 22, 2017
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Ashwani Kumar 2
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Mamta Satywali
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Sep 22, 2017
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Is it zero ?
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sourav.
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Sep 22, 2017
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should be $3$.Is it $3$?
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essential prime implicants are 2
nikkey123
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Sep 22, 2017
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I got a K-map with the following boolean function: F(A,B,C,D) = ΠM[3,4,6,9,11,14]+ Σd[0,7,8,10,13,15] In the following K-map following prime-implicants are considered: But I can chose ($\bar{A}$+$\bar{D}$) instead of ($\bar{A}$+$B$) like: So now ... $\bar{C}$+$\bar{D}$)($A$+$C$+$D$) So we get different f in the two cases or am I making a mistake somewhere?
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`JEET
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Essential prime implicants
The number of the essential prime implicant of the following function F is $F(w,x,y,z) = \Sigma m(0,2,5,7,8,10,12,14,15)$
`JEET
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Dec 26, 2018
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