in Programming in C
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1 vote
1 vote
Main()

{

char far *s1,*s2;

Printf("%d%d",size of(s1),sizeof(s2));

}
in Programming in C
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2 Comments

Prints the size of pointer, it depends on address bits
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2 Answers

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Size of the pointer will be printed.This question is compiler dependent.
some compiler assumes pointer is of 8bytes.

So output would be 88 if pointer is of 8 bytes.
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Answer given in book is 4 2 how???

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