token count for shorthand operators

Question

How many tokens are there in the following statement:

x >> = 2;

 

In general, are shorthand operators counted as a single token as ">>=" or double as ">>" and "=". Or anything else?

Answer 1

compiler follows greedy approach and will try to make longest pattern available. like x++ will be 2 token instead of x , + ,+ (3)

So here "01" , "!=" and ">>=" will be treated as 1 token only..

https://en.wikipedia.org/wiki/Operators_in_C_and_C%2B%2B#Compound_assignment_operators

Comments

@joshi_nitish Can you provide any link to read this?

---

see this

---

nothing is showing in the link, please update and thanks for telling me that it is a single token

PS

#define is not a token