C CODING

Question

#include <stdio.h>
 
int main()
{
    float a=5.375;
    char *p;
    int i;
    p = (char*)&a;
    for(i=0; i<2; i++)
        printf("%x", (unsigned char)(p[i]^p[3-i]));
 
    return 0;
}

Explain in detail

Comments

This is not in DETAIL, but it should print two values, first one is $XOR$ of 1st and $4$th Byte of $a$ and second one is $XOR$ of $2$nd and $3$rd Byte of $a$. What we need to do is to figure out the float point representation of $a$ for a $4$ byte container.

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Can you explain how it is XOR ?

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http://www.geeksforgeeks.org/interesting-facts-bitwise-operators-c/

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Thanks for link understood.

Answer 1

Assuming the machine is little endian.