UGC NET CSE | November 2017 | Part 2 | Question: 6

Question

The Boolean function with the Karnaugh map

is

• A. $(A+C) \cdot D+B$
• B. $(A+B) \cdot C +D$
• C. $(A+D) \cdot C+B$
• D. $(A+C) \cdot B+D$

Answer 1

The minimized expression is: $AD+CD+B$ or $(A+C).D+B$

Option $(A)$ is correct.