Hash table size is M ($2^{K}$) then LSB 'K' bits will decide the slot in hash table.
Here Hashtable size=8 ($2^{3}$) so LSB '3' bits will decide the slot .
01010010 -- it goes to 010 slot without collision.[without collision also one probe]-----${\color{Red} 1}$ probe
11011011---it goes to 011 slot without collision .${\color{Red} 1}$ probe
10011010--it goes to 010 slot but it is already filled so use linear probing and next slot also collision
it goes to 100 slot .No of probes generated here are ${\color{Red} 3}$
11111011--Same as above it also collide with existing slots and finally allocated in 101 slot.No of probes generated here are ${\color{Red} 3}$
01110010---Same as above it collides and finally allocated in a 110 slot .No of probes generated here are ${\color{Red} 5}$
Finally total no of probes generated are :1+1+3+3+5=13.