Each process from p1 to p10 require Si unit of resource for its completion.
To be in deadlock give each process 1 less than the actual resource requirement..
p1-->(s1-1)
p2-->(s2-1)
.
.
.
p10-->(s10-1)
now take summation 10*(s1+s2+...s10)-10=10*$\sum_{i=1}^{10}$ - 10 this is the minimum number of resource acquired by all the process to be in deadlock.
To avoid deadlock you just need to provide one more resource.
i.e X=10*$\sum_{i=1}^{10}$ - 10 + 1 and
X<=7(the resources provided to each process must not exceed the total available resource)
10*$\sum_{i=1}^{10}$=16 Ans