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Doubt in CSL and CFL
Tuhin Dutta
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Theory of Computation
Dec 4, 2017
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$a) \{\ 0^i\ 1^j\ 2^k\ \ | where\ i\ \neq j\ or\ j\ \neq k\ \}$
$b) \{\ 0^i\ 1^j\ 2^k\ \ | where\ i\ \neq j\ and\ j\ \neq k\ \}$
a) CFL(union of two OR-ed comparisons )
b) CSL( Double comaprison )
Am I correct?
theory-of-computation
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Tuhin Dutta
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Dec 4, 2017
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Tuhin Dutta
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abhishek tiwary
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Dec 4, 2017
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yes 1 is CFL 2 CSL
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Ashwin Kulkarni
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Dec 4, 2017
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Yes your reasons are also correct.
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It can be analyse in this way also CFL is not closed under intersection so it takes single comparison means union
CFL closed under intersection (and) so it takes double comparison
Both are correct
Ram Swaroop
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Dec 19, 2018
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