@ Parshu gate
For this schedule T2->T1->T3
Yes T1 is reading the data item for the first time but it is not actually reading the value of the data item that was before the start of all the transactions as it will be overwritten by T2.
So, this is not VS
i and vi
No cycle in polygraph and possible order is T1->T2->T3 according to the topological order of polygraph.
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