My work: $1+0.1*5+0.05*50=4ns$ Now please give me reasoning about : missing in $L1$ i will access $L2$ and i did that now When i am missing in $L2$ isn`t this obvious that i have actually missed in $L1 $ or should i mention it by $0.05*0.1*50$ Thanks!
you can see this...
they said that its 2 level cache...
means one after another....
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