iam confused
Then put k = n-1
to get T(1) for termination.
So you will get
T(n) = (n-1)*n + T(1) => n2 - n + 1 => O(n2)
@Ashwin Kulkarni thanks bro but iam asking why everytime we take till T(N-1) AND T(N-2)
what if i write T(n) = T(n-2) + n + (n-1) can we solve like this
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