Gateforum-Pure Aloha Numerical

Question

Groups of user stations(N) share a 56Kbps pure aloha channel. Each station outputs a 1000 bits frame on an average of once every 100sec(stations are buffered). What is the max value of N?

Answer is 1030. Please give detailed solution.

Comments

In pure aloha, the maximum efficiency is 0.184.
Hence effective bandwidth = 0.184 × 56 kbits/sec = 10300 bits/sec.

Each station requires 1000 bits / 100 sec = 10 bits/sec.

So, N = 10300/10 => 1030 stations.

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Thank you @Ashwin Kulkarni :)

Answer 1

effective bandwith=no of stations * capacity of each station=efficiency* bandwidth

capacity of each station=1000/100=10

N * 10   =   0.184 * 56 *1000

N = (0.184*56*1000)/10

N=1030.4

N=1030