I am solving with Pigeon Hole Principle. Please correct me if I am wrong.
Considering the required number of books as pigeons, days of the month as pigeonholes with 3 pigeons per day.
if my approach is wrong, please correct me
month can be of 30 or 31 days , 7 poems can keep her busy for 35 days :P
to create different sets of 3 we need to choose 3 poems out of 7 poems
7C3 = 35
@Mk Utkarsh,
Can you please explain this statement?
7 poems can keep her busy for 35 days :P
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