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How many number of false essential prime implicants for the given Boolean functions f(A,B,C) = $\sum{m(0,3,7)}.$
in Digital Logic
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ohh , so good information :)
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Ok, I got it.

"False EPI = EPI of POS form Kmap"

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  • The maxterm is called false minterms.
  • the prime implicant obtained by using the maxterm is called a false prime implicant.
  • the FPI which contains at least one $0$ which cannot be covered by other FPI is called essential false prime implicant.

Here false PI=3 and essential false prime implicant=2 

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1 Answer

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in this case epi=pi=2 but if we are make single term ring in two pair  ring then it is wrong because here copletely share by two term ring   if cosider then it is wrong