lets generate the regular expression of each .
x = denotes 0 or 1 occurence of symbol x. So either it will be epsilon or 1 .
String to be generated :- bbaacabc
The regular expressions :-
T1 : (b+c) * a + a ( b + c ) * a
T2 : (a+c)* b + b ( a + c ) * b
T3 : (b + a) * c + c ( b + a ) * c
lets see which regular expression generations the longest possible prefix
String = bbaacabc
T1 : bba
T2 : bb
T3 : bbaac
So , as we can see T3 is generating the longest possible prefix here
Now , again in the string (abc) also need to be generated , lets check which regular expression generates (abc).
T1 : end with a , but we want to end with c – so abc not possible
T2 : end with b , but we want to end with c – so abc not possible
T3:- (b + a ) * c – ending with c and also b and a can be generated inside the closure – so , yes T3 can generate abc.
Therefore total string (bbaacabc) is generated using T3T3.
So, Answer is option (D) T3T3