Test series

Question

$\text{What is three address code representation of this ?}$

-a+b|c^d^e*f|g

Comments

what is '|' ?

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Sir, It is Bitwise OR

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ok, then corresponding 3-addr code will be,
Note: i have taken ^ as exponential operator, otherwise if it is bitwise XOR, answer given by @Reena is correct below

t1=-a

t2=t1+b

t3=d^e

t4=c^t3

t5=t4*f

t6=t2|t5

t7=t6|g

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I expecting same..thank you sir

Answer 1

$^$ :Bitwise exclusive OR.

$|$ :bitwise inclusive OR.

$t1$=$e*f$

$t2=-a+b$

$t3$ $=$ $c$ $^$ $d$

$t4=t3$ $^$ $t1$

$t5=t2|t4$

$t6=t5|g$

NOTE: exclusive OR has higher precedence than bitwise inclusive OR in C.

Comments

Please look above one I think that is Right