How to solve #defined ?

Question

What is the output of the following C program?

#include<stdio.h>
#define SQR(x) (x*x)
int main()
{
    int a;
    int b=4;
    
    a=SQR(b+2);
    printf("%d\n",a);
    return 0;
}

• A. 14
• B. 36
• C. 18
• D. 20

Comments

My answer is 36, it is correct or not?

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14 is the answer because it will be evaluated as:-

b+2*b+2=4+2*4+2=4+8+2=14

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Answer is 14 . # define is a macro definition . It replaces SQR(b+2) with (b+2*b+2).So a is computed as 14.

Note the placing of the brackets.

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a=b+2*b+2

 =4+2*4+2

 =4+8+2 = 14...

Answer 1

As it is given (x*x) : The result will be b+2*b+2 which means: 4+2*4+2 = 14

Had it be ((x)*(x)): The answer would have been ((b+2)*(b+2)) = 36