C programming [closed]

Question

Answer 1

The concept involved in the question is that arrays are passed by pointers and so when we pass an array to fun() we will actually be passing a pointer of that array.
The answer to this question would depend on the implementation of data types by the machine/compiler and amount of bytes given to each.As per the solution it seems they have taken pointers as 4 bytes and integers as 2 bytes. So arr_size evaluates to 2 ,(notice that even though syntax of fun(int arr[]) when passed would be converted to a pointer int *arr and its size would be 4 bytes.)
so as arr_size evaluates to 2 first 2 elts will get printed.

Answer 2

Hope this helps :)