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Question

Answer 1

1500 rotation -------->   1 sec

1 rotation ---------->  $\frac{1}{1500}$ sec

Avg rotation time = $\frac{1}{1500 × 2}$ sec = 0.33 ms

Now 1 track data in 1 rotation

i.e   1000 byte -------> $\frac{1}{1500}$ sec

    1500 byte  --------> $\frac{1 × 1500}{1000 × 1500}$ =  1 ms

Seek time given = 15 ms

Total access time = Avg Seek time + Avg Rotation time + Data transfer time

 = 15 ms + 0.33 ms + 1 ms = 16.33 ms