MCQs in computer science

Question

Comments

a*b*c => either you do (a*b)*c or a*(b*c), result is same. So you can't identify the order of evaluation.

Similarly,

a+b+c =(a+b)+c=a+(b+c)

a&&b&&c = (a&&b)&&c = a&&(b&&c)

but in case of % =>

a%b%c => (a%b)%c ≠a%(b%c)

therefore, based on the result, you can find out the order of evaluation.

@Rishav Kumar Singh  Is my answer correct?

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@Ashish Goyal

brother order of evaluation means, which one evaluates first, it doesn't depend upon result.

in C, they defined the order of evaluation for only 4 operators

1) expr₁ && expr₂   ====> expr₁ evaluates first if it true then only expr₂ evaluates

2) expr₁ || expr₂   ====> expr₁ evaluates first if it false then only expr₂ evaluates

3) expr₁ , expr₂   ====> expr₁ evaluates first then expr₂ evaluates and return the value of expr₂

4) expr₁ ? expr₂ : expr₃   ====> expr₁ evaluates first if ( it true then only expr₂ evaluates) else ( then only expr₃ evaluates )

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@Shaik Masthan

Thanks for the elaboration. I misunderstood the question. It is clear now

Answer 1

The answer is && i.e. option D since the order of evaluation for the operator & & is defined by the language whereas * and + will be evaluated  depending on the type of Associativity.