Duality of Function

Question

Let f(x,y,z)=wy+w'y'. The function is ______.

1.only dual

2. not dual

3.None

4.self dual

 

Please provide the answer with solution ?

Comments

Check the question and options

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shaik why u are saying check question and options ?

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in the question there is no z variable in Function

i mean f(x,yz) ===> where is w?

coming to options:-

what is the meaning of only dual and No dual ?

i heard Self-dual only till now. ( may be i miss those )

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Shaik u can just expand the expression to get 'z'.

Answer 1

I think there is a misprint in the question, but if I consider w as x or z in both cases answer is 3. None

Comments

rtiwari95 ,you can just expand the expression and get 'z' .

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rtiwari95 why the answer will be 'None'. Can u explain ?

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if we take w as z, then

f(x,y,z) = yz+y'z' ; AND  is commutative

Now converting to canonical SOP form

f(x,y,z) = xyz+x'yz+xy'z'+x'y'z' = m7+m3+m4+m0

here, m3 is complement of m4 and m7 is complement of m0

According to duality theorem no mutually complement terms should come together in SOP.

That's why answer is none.

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rtiwari95 ,whatever you are saying is the condition for selfduality and not for duality. So your approach is wrong.