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How many ways are there to seat six people around a circular table where two seating are considered the same when everyone has the same two neighbors without regard to whether they are right or left neighbors?
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In the above image see the two seatings, in both the seatings everyone have same neighbour.

So when calculating the permutations consider them as same and not different.

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total no of ways six people around a circle table is 5!+120

but if left right neighbor of a people  is same as right left neighbor  for all 6 people then they we be consider as same  means no we get should be divided by 2   (see the image in comment  by sakharam )

so answer is 120/2=60

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