in Probability
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in Probability
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0.224
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$\lambda = 3$

$P(k) = e^{- \lambda} \frac{\lambda ^k}{ k!}$

$P(2) =$$\large e^{- 3} \times \frac{3 ^2}{ 2!}$

$P(2) = 0.22404$
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@utkarsh

How do we get know  lambda and k from the question?
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180 calls per hour so 3 calls per minute
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