Q can be anything
Take P as ∅
∅L = ∅
so, L can be anything
Let the operation is concatenate. as no operation is given . i think we should consider it as concatenate. so Q may or may no be regular for ex . p=X | x∈(a+b)* now assume that q be a language ww. w belong to the same domain as x. so now the new language p.q= L={xww∣w,x∈(a+b)∗}
xww which will be regular. q may or may not be regular and cfl . it can be csl also..
for more .:http://gatecse.in/wiki/Identify_the_class_of_the_language
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