The Given Address 192.168.19.24/29
step one convert mask to binary i.e. 29 bits are reserved. so make it binary one
( IP address is belong to class C so 24 bits are of class C and of last 5 bits borrowed from host so (29 mask)
11111111.11111111.11111111.11111000
convert only last value 24 from 192.168.19.24 to binary bcz its class C now i.e. 11000
11111111.11111111.11111111.11111000
00011/000 24 in binary { first five bits dont change bcz they are net id}
00011001 first address (192.168.19.25)
00011110 last address (192.168.19.30)
00011111 broadcast (192.168.19.31)
now range is from 192.168.19.25 to 192.168.19.30 answer os C
00
tell me how to upload image as a answer. i solved neatly in notebook so