in Calculus
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Differentiate

y=$x^{-1/lnx}$
in Calculus
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try taking log both sides
0
0

1 Answer

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y = x^(-1 / lnx)

ln y = (-1/lnx) * lnx

y = e^-1

thus derivative is 0

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aditi19 asked in Calculus Oct 25, 2018
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aditi19 asked in Calculus Oct 25, 2018
by aditi19
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