in how many ways 4 different balls can be placed in 5 different boxes so that no box contains all 4 balls

Question

in how many ways 4 different balls can be distributed in 5 different  boxes so that no box contains all 4 balls

Comments

what if balls  and boxes both are numbered

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i think its already mentioned that different balls and different boxes if those are numbered then any ball can go into any 5 boxes. so required ways are = $5^{4} - 5 $.

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Yes it should be $5^4 - 5$  as  Shubhgupta said.

Any ball can go into any box $5^4$

balls should not be going to same box $5$

total=$5^4 - 5$

 

 

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this may help https://gateoverflow.in/132665/%23discrete-%23combinatorics