NIELIT 2018-20

Question

The general solution of the differential equation $\frac{dy}{dx} = (1+y^2)(e^{-x^2}-2x \tan^{-1} y)$ is:

• A. $e^{x^2} \tan^{-1} y = x+c$
• B. $e^{-x^2} \tan^y = x+c$
• C. $e^x \tan y = x^2+c$
• D. $e^{-x} \tan^{-1} y = x^3+c$