ee gate 2014

Question

minimum of the real valued function f(x)=(x-1)^2/3 occurs at x equal to ??

how to find the value of when equating f’(x)=0???

Comments

actually it is not differential at x=1 ,we can write this, $(\sqrt[3]{(x-1)})^2$ we can see at x=1 ,it will give 0 which is minimum value .

---

ok but there will be square  on over cuberoot??

---

it is corrected now , thank you

---

thank u for help