in Theory of Computation edited by
609 views
0 votes
0 votes
If $L = \{a^nb^n : n\geq 0\}$
then, $L^2=?$
in Theory of Computation edited by
by
609 views

4 Comments

How you all are tagging to other users I have also written correct names but it is just plain text
0
0
to tag someone, first type @, then type name
0
0
@Shaik Masthan
0
0

1 Answer

0 votes
0 votes

$L^2 =L.L =a^nb^na^mb^m |n,m>=0$

edited by

Related questions