in Operating System
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1 vote
1 vote

in Operating System
657 views

4 Comments

If first 2 lines of all 3 programs are executed, then P0 will keep waiting for C, P1 will keep waiting for B, P2 will keep waiting for D.
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@Hardik Vagadia What explanation is given in solution key of RBR?

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Strange !! I can type ACE, I can type MadeEasy, but I can't type RBR ..
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1 Answer

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both B and D are common so both can cause deadlock when execution happen the way which @Kunal Kadian wrote!!!!

but how test series answers of RBR are wrong.strange!!!

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