what is the use of void in main(void)?
my code is:
#include <stdio.h>
#include <conio.h>
int main(int argc,char *argv[])
{
int i;
if( argc >= 2 )
{
printf("The arguments supplied are:\n");
for(i = 1; i < argc; i++)
{
printf("%s\t", argv[i]);
}
}
else
{
printf("argument list is empty.\n");
}
return 0;
}
i run this code with and without the arguments in main() it works fine i.e., it is printing the arguments
My doubt is even though i write void in the main(void) the above code is working fine,
i am confusing why it is working i am thinking that if i pass void in the main(void) the program should not take any value…..
anyone please tell me what is the reason and what is the use of void in the main(void)
