Ace Test Series: DBMS - Functional Dependency

Question

 

Comments

Well Consider

       A            B

       2             X1

       4             X2

Now if u put any value in X it will always satisfy A -> B.

Becasue to violate it I should have two entries of A to be same pointing to different values of B like:

       A            B

       2             4

       2             3

Here A -> B doesn't exists

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That's exactly what the question asks i guess, what you explained in the first point so B may agree or disagree still the FD hold.

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ohk i got that thnks