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Question

100 nodes are connected to a 1000 meter length coaxial cable,using some protocol each node can transmit 50 frames/sec.

where the average frame length is 2500 bits.the transmisson rate at each node is 100 mbps.what is the numeric value of efficiency of the protocol(in %)?

Comments

can we approach like this- > 

node can transmit at = 50*2500 bits/sec

transmission rate at node = 100*10^6 bits/sec

so efficiency = (50*2500 / 10^8 ) * (100) %

Answer 1

80%....

Given configuration can send only 40 frames instead of 50 frames...

Comments

cannot get this.

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RTT= 10 microsec

Aggregate bandwidth = 10000mbps

(RTT * bandwidth)/2500bits

40 frames....actually able to send 50 frames...