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if initially given that sender send 2mss

Then how slow start will it be

2mss,4mss,8mss,........

And conestion avoidence will be increament by +2 each time or +1.

Please suggest me these are right or wrong
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3 Answers

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We start the "slow start phase" with the window size given .... but after the threshold we always increase by 1MSS So according to your question if threshold is at 16MSS then you will do like 2 4 8 16 and then 17 18 till timeout.
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Here slow starts with 2 MSS, and in congestion avoidence will always be +1 in terms of MSS

if it would be given  1 MSS = x KB then in terms of Data it would be adding +x each time
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If congestion is detected then it will increase exponentially up to 50% where congestion is detected and then after that it will start increasing linearly.

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