What is the output of program?

Question

void f(int x,int &y,const int &z)
{x+=z;
    y+=z;
}
int main()
{
    int a=22,b=33,c=44;
    f(a,b,c);
    f(2*a-3,b,c);
    
    printf("a=%d b=%d c=%d",a,b,c);

    return 0;
}

Comments

This code must through an error

Answer 1

Note:-func(int &a) means it'll receive the address of the argument being passed when the function is invoked with func(int x) in some caller module(main() function in this case).In other words it is call by reference and any change of "a" inside func() will reflect in the caller module.

Now,initially:-a=22,b=33,c=44(given in the snippet),we need to worry about value of "b" & "c" only,as second and third parameters of the function signature are as highlighted "void f(int x,int &y,const int &z)" and the function is called as "f(int a,int b, int c)".Now as 3rd argument is treated as constant and it's never updated in "f()" we don't need to worry about "c" also,and it'll remain constant throughout.Only "b" will be modified as "y" is updated in "f" function as follows:-

Dry run table

	a	b	c
Intially	22	33	44
After f(a,b,c)	22	(33+44)=77	44
After f(2*a -3,b,c)	22	(77+44)=121	44

So,a=22,b=121,c=44 is the final output

Comments

$77+44=121 $

So answer is 22, 121, 44