How do we perform 0 – 1 in 2’s complement subtraction using 1-bit register??
For 0 - 1
Using 2's complement in we could represent only -1 and 0 when no of bits=1.
The 2's complement of 1 is 1 and when we add 0 with 2's complement of 1 then we get1 as the answer and no carry and that is why we have a borrow of 1??
Result should be in 1 bit
right?
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