in Computer Networks
1,069 views
0 votes
0 votes
A $64000$-byte message is to be transmitted over a $2$-hop path in a store-and-forward packet-switching network. The network limits packets toa maximum size of $2032$ bytes including a $32$-byte header. The trans-mission lines in the network are error free and have a speed of $50$ Mbps.Each hop is $1000$ km long and the signal propagates at the speed of light ($3×10^8$meters per second). Assume that queuing and processing delays at the intermediate node are negligible. How long does it take to deliver the entire message from the source to the destination?

I am getting answer as $1*3*(T_t+T_p) + \;31*T_t$ where $T_t=0.325\; ms$ and $T_p=3.333\; ms$. Please Confirm.
in Computer Networks
1.1k views

4 Comments

@noob_coder

Please share the link of that problem of foreign university exam. 

0
0
is answer = 17.56 ms
0
0
I don't have the answer.
0
0

1 Answer

0 votes
0 votes

i am getting 113.175 msec

3 Comments

when the first packet will reach at destination the second packet is just on one T.t away isn't . why did u consider as t.p ?

1
1
for first packet – 3*0.325+3*3.33=10.965ms

for rest 31 packet differ by only transmission time

so overall =>10.965(first packet)+31*0.325(31 packets)=21.04ms
0
0
The answer I got is 21.05 ms
0
0

Related questions