in Digital Logic
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Is Y' + Z' same as (YZ)' ?

Please explain this concept of compliments..!!
in Digital Logic
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Thanks 😊
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4 Answers

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Yes they are the same. This is due to De Morgan's Law.
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Y Z Y' + Z' (YZ)'
0 0 (1 + 1) = 1 (0.0)' = (0)' = 1
0 1 (1 + 0) = 1 (0.1)' = (0)' = 1
1 0 (0 + 1) = 1 (1.0)' = (0)' = 1
1 1 (0 + 0) = 0 (1.1)' = (1)' = 0

The result is due to de Morgan's law, but you can confirm it for yourself using a truth table.

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Oh yeah ! thanks for the better idea 👍
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Thanks for the idea
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Yes,this is true due to De'morgans law
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YES  it is same. by applyind demorgans law.

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