in Combinatory edited by
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4 votes
4 votes

How many cards must be selected from a standard deck of $52$ cards to guarantee that at least three hearts are present among them?

  1. $9$
  2. $13$
  3. $17$
  4. $42$
in Combinatory edited by
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3 Comments

Answer will be $42$, with pegion hole principle
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Rosen example..
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how would it be applied? please show.
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1 Answer

5 votes
5 votes

In this the worst case will happen as follows :-

$1^{st}$ $13*3 = 39$ cards that we pick up turns out to be any one of daimond or spades or clubs but not hearts i.e.

 

Now when we pick the next $3$ cards they are guaranteed to be hearts.($\because$ we have already picked cards from all other suits)

 

$\therefore$ We need to pick $13+13+13+3= 42$ cards in order to guarantee that there are atleast $3$ cards of hearts in the selected cards.

So option $4$ is the correct option.

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3 Comments

Thats not exactly the worst case. In worst case the first 39 will not have any heart -- but they can be in any order. To be more precise, by having only $2$ hearts, we have only $39$ other cards and these $41$ can be in any order.
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I did not get .plz can u explain it in more words?
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The worst case, we may select all the clubs,
diamonds, and spades (39 cards) BEFORE ANY HEARTS. (i.e 13 clubs+ 13 diamonds +13 spades, which is equal to 39 cards)
 So, to guarantee that at least three hearts are selected,
39+3=42 cards should be selected.
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Answer:

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