ISI2014-DCG-53

Question

The value of the integral $\displaystyle{}\int_{-1}^1 \dfrac{x^2}{1+x^2} \sin x \sin 3x \sin 5x dx$ is 

• A. $0$
• B. $\frac{1}{2}$
• C. $ – \frac{1}{2}$
• D. $1$

Comments

$0$?

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yes

Answer 1

It’s a odd function . because sin(-x) = – sinx.