ISRO2020-78

Question

In the following procedure

Integer procedure P(X,Y);
Integer X,Y;
value x;
begin
      K=5;
      L=8;
      P=x+y;
end

$X$ is called by value and $Y$ is called by name. If the procedure were invoked by the following program fragment

K=0;
L=0;
Z=P(K,L);

then the value of $Z$ will be set equal to

• A. $5$
• B. $8$
• C. $13$
• D. $0$

Comments

I think Error will come.

Value x ;

what it means and y is not even declared here.

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I think answer will be 8

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variable is not declared here, Did anyone get the value for this ??

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@kpckpc this is pseudo-code so, do not consider any typing error... 

Answer 1

X=call by value  hence we pass 0 ,

Y=call by name hence we pass expression or variable and evaluate every time

After passing the value as ‘0’ and name as ‘L’

P=0+L   // here L=8 ;

P=8; / return

Z=8

Answer  B

Comments

But how to decide which value to be taken? Why L=8 and not 0?

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X is called by value simply means actual value will be used irrespective of whatever value inside the function that is 0

Y is called by name means address of var will be used so value will be changed after calling the function Y=8