Consider a non-pipelined processor operating at $2.5$ GHz. It takes $5$ clock cycles to complete an instruction. You are going to make a $5$- stage pipeline out of this processor. Overheads associated with pipelining force you to operate the pipelined processor at $2$ GHz. In a given program, assume that $30\%$ are memory instructions, $60 \%$ are ALU instructions and the rest are branch instructions. $5 \%$ of the memory instructions cause stalls of $50$ clock cycles each due to cache misses and $50 \%$ of the branch instructions cause stalls of $2$ cycles each. Assume that there are no stalls associated with the execution of ALU instructions. For this program, the speedup achieved by the pipelined processor over the non-pipelined processor (round off to $2$ decimal places) is_____________.