UGC NET CSE | January 2017 | Part 3 | Question: 30

Question

A node $X$ on a $10$ Mbps network is regulated by a token bucket. The token bucket is filled at a rate of $2$ Mbps. Token bucket is initially filled with $16$ megabits. The maximum duration taken by $X$ to transmit at full rate of $10$ Mbps is ______secs.

• A. $1$   
• B. $2$ 
• C. $3$
• D. $4$

Comments

Sir it's

16Mbits / (10Mbps - 2Mbps )= 2sec

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https://gateoverflow.in/111026/net-jan-17-paper-3-q30-token-bucket

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16+2*x=10*x

x=2 sec

Answer 1

Maximum burst time = Capacity /(Output rate-Arrival rate  ) = 16/(10-2) = 2 seconds

Answer 2

Using $T=\frac{C}{R_{out}-R_{in}}$ ans comes out to be 2 sec(where C=16Mbits $R_{out}$=10Mbps and $R_{in}$=2Mbps)......:-)

Answer 3

In token bucket algo

$C+\rho * S = M * S \\ C= Capacity \ of \ bucket \\ \rho = Token \ arrival \ rate \\ M = Maximum \ Output \ rate \\ S = Burst \ Time$

S = (16-2)/8 = 2 sec 

Hence option 2) is correct

Answer 4

2) 2 s