NIELIT 2017 July Scientist B (CS) - Section B: 30

Question

If each address space represents one byte of storage space, how many address lines are needed to access RAM chips arranged in a $4\times 6$ array, where each chip is $8K\times 4$ bits?

• A. $13$
• B. $14$
• C. $16$
• D. $17$

Answer 1

Option D

Size of each Ram chip $= 8K*4 bits = 2^{3}*2^{10}*2^{2} = 2^{15} bits = 2^{12} bytes$, it can be represent  by $12 bit$

number of chips required $= 6*4 = 24 $

$5$ bits can represent $24$ chips

So, total number of bits required$ = 12 + 5 = 17 bits$