$\text{Here, matrix A is a real idempotent matrix of size $4 \times 4$ for which possible eigen values are 0 and 1. }$
$\text{Proof: Let, $v$ is an eigenvector associated with eigenvalue $\lambda.$}$
$\text{$\lambda v = Av$}$
$\text{$\lambda v = A^2v$}$
$\text{$\lambda v = \lambda^2v$}$
$\text{$ \lambda^2v – \lambda v = 0$}$
$\text{$ (\lambda^2- \lambda)v = 0$}$
$\text{$\lambda=0,1$}$
$\text{Here,}$
$\text{So, Trace(A) = $\lambda_1 + \lambda_2 + \lambda_3 + \lambda_4 $}$
$\text{Trace(A) = 4, when all $\lambda’s$ are 1, It is possible when A is identity(only possible non-singular matrix) }$
$\text{Trace(A) = 3, when any 3 $\lambda’s$ are 1 and other is 0 }$
$\text{Trace(A) = 2, when any 2 $\lambda’s$ are 1 and rest are 0 }$
$\text{Trace(A) = 1, when any 1 $\lambda’s$ is 1 and rest are 0 }$
$\text{Trace(A) = 0, when all $\lambda’s$ are 0 }$
$\text{So, $S=\{0,1,2,3,4\}$}$