The following expression was to be realized using $2$-input AND and OR gates. However, during the fabrication all $2$-input AND gates were mistakenly substituted by $2$-input NAND gates. $(a.b).c + (a'.c).d + (b.c).d + a. d$
What is the function finally realized ?
Option (C) is correct!
@Nitesh Singh 2 thank bhaiyya,help ho gyi
The final answer will come as: $a'+c'+d'+a'c+ab+bc$ $= a'(c+1)+c'+d'+ab+bc$ $=a'+c'+d'+ab+bc$ $=(a'+a)(a'+b)+(c'+c)(c'+b)+d'$ $=a'+b+c'+b+d'$ $=a'+b+c'+d'$ Option is C.
Hira Thakur sir, there is a difference in both question, see the 3rd term.
in GATE PYQ : (b.c).d
in GO2017 Qus : (b¯.c).d
Hey anyone ,Can I use kmaps anywhere like I am minimizing a expression using properties and got stuck
Can I use kmaps now???
Or I have use original expression
@Sachin Mittal 1 @arjun @Deepak Poonia sir
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