NIELIT Scientist B 2020 November: 37

Question

 

Find the odd one out in the given series:

$ZA, RS, DE, JK, PR, LM, YZ, NO$

• A. $JK$
• B. $LM$
• C. $ZA$
• D. $PR$

Answer 1

Given series $:ZA,RS,DE,JK,PR,LM,YZ,NO$

We know that $Z = 26,A = 1,R = 18,S = 19,D = 4,E = 5,J = 10 ,K = 11,P = 16, R = 18,L = 12, M = 13,Y = 25, Z = 26,N = 14 , O = 15. $

The difference between each pair is $1,$ but $PR$ doesn’t follow.

So, the correct answer is $(D).$

Answer 2

According to the given series each term is $+1$ to the next term.

• $ZA\implies Z+1=A$
• $RS\implies R+1=S$
• $DE\implies D+1=E$
• $JK\implies J+1=K$
• $PR\implies P+2=R$
• $LM\implies L+1=M$
• $YZ\implies Y+1=Z$
• $NO\implies N+1=O$

Here $PR$ not follow the pattern. Option D is correct.